NHCC Enthalpy Change in Burning 3 Moles of Liquid Nonane Questions
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The compound nonane, C9H20, is a good fuel. It is a liquid at ordinary temperatures. When the liquid is burned, the reaction involved is
C9H20(?) + 14 O2(g)
9 CO2(g) + 10 H2O(g)
The standard enthalpy of formation of liquid nonane at 25 °C is -274.7 kJ mol-1; other relevant enthalpy of formation values in kJ mol-1 are:
C9H20(g) = -228.2 ; CO2(g) = -393.5 ; H2O(g) = -241.8
(a) Calculate the enthalpy change in the burning of 3.000 mol liquid nonane to form gaseous products at 25°C. State explicitly whether the reaction is endothermic or exothermic.
?H° = kJ
endothermicexothermic
(b) Would more or less heat be evolved if gaseous nonane were burned under the same conditions?
moreless
What is the standard enthalpy change for vaporizing 3.000 mol C9H20(
) at 25°C?
?H° = kJ
Calculate the enthalpy change in the burning of 3.000 mol gaseous nonane to form gaseous products at 25°C.
?H° = kJ
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